用动态扫描方法和定时器1在数码管的前三位显示出秒表，精确到1%秒，即后两位显示1%秒，一直循环下去？

好酷屋教程网小编为您收集和整理了用动态扫描方法和定时器1在数码管的前三位显示出秒表，精确到1%秒，即后两位显示1%秒，一直循环下去？的相关教程：//用动态扫描方法和定时器1在数码管的前三位显示出秒表，精确到1%秒，即后两位显示1%秒，一直循环下去。#include#defineuintunsignedint#defineucharunsign

//用动态扫描方法和定时器1在数码管的前三位显示出秒表，精确到1%秒，即后两位显示1%秒，一直循环下去。

#include

#define uint unsigned int

#define uchar unsigned char

sbit wela=P2^7;

sbit dula=P2^6;

uchar code table[]={

0x3f,0x06,0x5b,0x4f,

0x66,0x6d,0x7d,0x07,

0x7f,0x6f,0x77,0x7c,

0x39,0x5e,0x79,0x71};

void init();

void display(uchar fen,miao1,miao2);

void delay(uchar);

uchar tt,fen,miao1,miao2;

uint temp;

void main()

{

init();

while(1)

{

if(tt==70)

{

tt=0;

temp++;

if(temp==600)

temp=0;

fen=temp/100;

miao1=temp%100/10;

miao2=temp%10;

}

display(fen,miao1,miao2);

}

}

void display(uchar fen,miao1,miao2)

{

dula = 1;

P0 = table[fen];

dula = 0;

P0 = 0xff;

wela = 1;

P0 = 0xfe;

wela = 0;

delay(1);

dula = 1;

P0 = table[miao1];

dula = 0;

P0 = 0xff;

wela = 1;

P0 = 0xfd;

wela = 0;

delay(1);

dula = 1;

P0 = table[miao2];

dula = 0;

P0 = 0xff;

wela = 1;

P0 = 0xfb;

wela = 0;

delay(1);

}

void delay(uchar z)

{

uchar x,y;

for(x=z;x>0;x--)

for(y=110;y>0;y--);

}

void init()

{

temp=0;

TMOD=0x01;

TH1=(65536-10000)/256;

TL1=(65536-10000)%256;

EA=1;

ET1=1;

TR1=1;

}

void timer1() interrupt 3

{

TH1=(65536-10000)/256;

TL1=(65536-10000)%256;

tt++;

}

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